تدرب وحل التمرينات

(1)- جد ناتج ضرب مقدار جبري في مقدار جبري كل منهما من حدين:

$(n-6{)}^2$

$(n-6{)}^2=n^2-12n+36$

$(y+5)(y-5)$

$(y+5)(y-5)=y^2-25$

$(x+\sqrt{8}{)}^2$

$(x+\sqrt{8}{)}^2=x^2+2\sqrt{8}x+8=x^2+4\sqrt{2}x+8$

$(y+\sqrt{6})(y-\sqrt{6})$

$(y+\sqrt{6})(y-\sqrt{6})=y^2-6$

$(8+h)(3+h)$

$(8+h)(3+h)=24+11h+h^2$

$(4-y)(5-y)$

$(4-y)(5-y)=20-9y+y^2$

$(2x-3)(x+9)$

$(2x-3)(x+9)=2x^2+15x-27$

$(z-2\sqrt{7})(2z-\sqrt{7})$

$(z-2\sqrt{7})(2z-\sqrt{7})=2z^2-5\sqrt{7}z+14$

(2)- جد ناتج ضرب مقدار جبري من حدين في مقدار جيري من ثلاثة حدود:

$(x+6)(x^2-6x+36)$

$(x+6)(x^2-6x+36)=x^3+216$

$(y-1)(y^2+y+1)$

$(y-1)(y^2+y+1)=y^3-1$

$(z-3{)}^3$

$(z-3{)}^3=z^3-9z^2+27z-27$

$(\frac{2}{3}-r)(\frac{4}{9}+\frac{2}{3}r+r^2)$

$(\frac{2}{3}-r)(\frac{4}{9}+\frac{2}{3}r+r^2)=\frac{8}{27}-r^3$

$(x-\sqrt[3]{4})(x^2+\sqrt[3]{4}x+\sqrt[3]{16})$

$(x-\sqrt[3]{4})(x^2+\sqrt[3]{4}x+\sqrt[3]{16})=x^3-4$

$(z-\sqrt{5}{)}^3$

$(z-\sqrt{5}{)}^3=z^3-3\sqrt{5}{z}^2+15z-5\sqrt{5}$

$(\sqrt[3]{\frac{1}{5}}+n)(\sqrt[3]{\frac{1}{25}}-\sqrt[3]{\frac{1}{5}}\mathrm{n}+{\mathrm{n}}^2)$

$(\sqrt[3]{\frac{1}{5}}+n)(\sqrt[3]{\frac{1}{25}}-\sqrt[3]{\frac{1}{5}}n+n^2)=\frac{1}{5}+n^3$

$(\sqrt[3]{\frac{1}{9}}+\frac{1}{h})(\sqrt[3]{\frac{1}{81}}-\sqrt[3]{\frac{1}{9}}\frac{1}{h}+\frac{1}{h^2})$

$(\sqrt[3]{\frac{1}{9}}+\frac{1}{h})(\sqrt[3]{\frac{1}{81}}-\sqrt[3]{\frac{1}{9}}\frac{1}{h}+\frac{1}{h^2})=\frac{1}{9}+\frac{1}{h^3}$